A) Calculate the growth rate constant for the following experiment:

t0 = 2h: N = 9.6x102, log10 N = 2.98
t = 8h: N = 4.7x106, log10 N = 6.67

µ = ( (log10 t - log10 t0) 2.303) / (t - t0)

Pick the correct calculation from the table below:

A)
µ = ( (6.67 + 2.98) 2.303) / (8 - 2)
= (9.65 x 2.303) / 6
= 22.22 / 6
= 3.70 hour-1

 B)
µ = ( (6.67 - 2.98) 2.303) / (8 - 2)
= (3.69 x 2.303) / 6
= 8.5 / 6
= 1.42 hour-1
C)
µ = ( (6.67 - 2.98) / 2.303) / (8 - 2)
= (3.69 / 2.303) / 6
= 1.60 / 6
= 0.27 hour-1

 D)
µ = ( (6.67 - 2.98) 2.303) / (8 + 2)
= (3.69 x 2.303) / 10
= 8.5 / 10
= 0.85 hour-1

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