Correct!

In this experiment, the point of equivalence is at A280 0.265 = 20µl antigen.

The A280 for BSA is 1.0 at 1.9mg/ml.

Calculate the A280 for antigen at equivalence:

A)

Amount of antigen = 20µl = 0.2mg

Concentration in cuvette = 0.1mg/ml

If 1.9mg/ml BSA gives an A280 of 1.0, then A280(Ag) = (0.1 x 1)/1.9 = 0.19.

B)

Amount of antigen = 0.02 x 4 (mg/ml BSA) = 0.08mg

Concentration in cuvette = 0.08mg/ml

If 1.9mg/ml BSA gives an A280 of 1.0, then A280(Ag) = (0.08 x 1)/1.9 = 0.042.

C)

Amount of antigen = 0.02 x 4 (mg/ml BSA) = 0.08mg

Concentration in cuvette = 0.04mg/ml

If 1.9mg/ml BSA gives an A280 of 1.0, then A280(Ag) = (0.04 x 1)/1.9 = 0.021.

D)

Amount of antigen = 0.02 x 4 (mg/ml BSA) = 0.08mg

Concentration in cuvette = 0.04mg/ml

If 1.9mg/ml BSA gives an A280 of 1.0, then A280(Ag) = 0.04 x 1.9 = 0.076.


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